Question

Radius of a certain orbit of hydrogen atom is 8.48 Å. If energy of electron in this orbit is E/x, then x = ______.
(Given a0 = 0.529Å, E = energy of electron in ground state)

Answer 1

We know:

$r = 0.529 \frac{n^2}{Z} \implies 8.48 = 0.529 \frac{n^2}{1}$

$n^2 = 16 \implies n = 4$

We also know:

$E \propto \frac{1}{n^2}$

$E_n = \frac{E}{16}$

Thus, $x = 16$.

Answer 2

We know:

$r = 0.529 \frac{n^2}{Z} \implies 8.48 = 0.529 \frac{n^2}{1}$

$n^2 = 16 \implies n = 4$

We also know:

$E \propto \frac{1}{n^2}$

$E_n = \frac{E}{16}$

Thus, $x = 16$.