Question

Radius of ${}_{2}^{4}He$nucleus is 3 Fermi. The radius of $3 \rightarrow 2$nucleus will be.

• A. 5 Fermi
• B. 6 Fermi
• C. 11.16 Fermi
• D. 8 Fermi

Answer 1

Answer: (C)

11.16 Fermi

Answer 2

We have

$r \propto A^{1/3} \Rightarrow \frac{r_{2}}{r_{1}} = \left( \frac{A_{2}}{A_{1}} \right)^{1/3} = \left( \frac{206}{4} \right)^{1/3}$

$\therefore r_{2} = 3\left( \frac{206}{4} \right)^{1/3} = 11.6\mspace{6mu} Fermi$.