Question

Radioactive ${}_{27}^{60}Co$ is transformed into stable ${}_{28}^{60}Ni$ by emitting two $\gamma$ rays of energies

• A. $1.33$ Me V and $1.17$ MeV in succession
• B. $1.17$Me V and $1.33$ MeV in succession
• C. $1.37$ Me V and $1.13$ Me V in succession
• D. $1.13$ Me V and $1.37$ Me V succession

Answer 1

Answer: (B)

$1.17$Me V and $1.33$ MeV in succession

Answer 2

: The successive emission of gamma rays of energies $1.17MeV$and $1.33MeV$from the de-excitation of ${}_{28}^{60}Ni$nuclei formed from $\beta -$decay of ${}_{27}^{60}Co.$ this process is shown in the figure through an energy level diagram.