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Question

Physics Question on Photoelectric Effect

Radiation of two photons having energies twice and five times the work function of a metal are incident successively on the metal surface.Find out the ratio of maximum velocity of photo electrons emitted in the two cases.

A

v1v2=13\frac{v_1}{v_2}=\frac{1}{3}

B

v1v2=14\frac{v_1}{v_2} = \frac{1}{4}

C

(\frac{v_1}{v_2} = 1

D

v1v2=12\frac{v_1}{v_2} = \frac{1}{2}

Answer

v1v2=12\frac{v_1}{v_2} = \frac{1}{2}

Explanation

Solution

The correct option is (D): v1v2=12\frac{v_1}{v_2} = \frac{1}{2}