Question

Radiation of frequency $2ν_0$ is incident on a metal with threshold frequency $ν_0$. The correct statement of the following is ______.

• A. No photoelectrons will be emitted
• B. All photoelectrons emitted will have kinetic energy equal to $hν_0$
• C. Maximum kinetic energy of photoelectrons emitted can be $hν_0$
• D. Maximum kinetic energy of photoelectrons emitted will be $2hν_0$

Answer 1

Answer: (C)

Maximum kinetic energy of photoelectrons emitted can be $hν_0$

Answer 2

According to Einstein’s photoelectric equation, the maximum kinetic energy $K_{max}$ of the photoelectrons is given by:
$K_{\text{max}} = h\nu - h\nu_0$
where ν is the frequency of incident radiation and $ν0$is the threshold frequency. If the radiation has a frequency $2ν0$, then:
$K_{\text{max}} = h(2\nu_0) - h\nu_0 = h\nu_0$