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Question

Mathematics Question on Binomial theorem

r and n are positive integers r>1,n>2r > 1, n > 2 and coefficient of (r+2)th(r+2)^{th} term and 3rth3r^{th} term in the expansion of (1+x)2n(1 + x)^{2n } are equal, then n equals

A

3r3r

B

3r+13r + 1

C

2r2r

D

2r+12r + 1

Answer

2r2r

Explanation

Solution

tr+2=2nCr+1xr+1;t3r=2nC3r1x3r1t_{r+2} = {^{2n}C_{r+1}} \,x^{r+1}; t_{3r} = {^{2n}C_{3r-1} } x^{3r-1} Given 2nCr+1=2nC3r1;{^{2n}C_{r+1} } = {^{2n}C_{3r-1}} ; 2nC2n(r+1)=2nC3r1\Rightarrow \, {^{2n }C_{2n -\left(r+1\right)}} = {^{2n }C_{3r-1}} 2nr1=3r12n=4rn=2r\Rightarrow 2n-r-1=3r-1 \Rightarrow 2n = 4r \Rightarrow n= 2r