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Question: Question: Out of two resolved components of a force, one is \(10\;N\) and it makes an angle of \({60...

Question: Out of two resolved components of a force, one is 10  N10\;N and it makes an angle of 60{60^\circ } with the force. The magnitude of the force is:
(A) 7.1  N7.1\;N
(B) 4.33  N4.33\;N
(C) 17.3  N17.3\;N
(D) 20  N20\;N

Explanation

Solution

In physics, a vector is a physical quantity that has both magnitude and direction. It is denoted with an arrow sign on top of the quantity, for example A\vec A. In order to signify just the magnitude of the vector, we can show this as A\left| {\left. A \right|} \right. or simply AA.

Complete step by step solution:
Any vector quantity possessing a magnitude and a direction can be divided into two different components, called the rectangular components.
Similarly, the force being a vector quantity can also be divided into two different components. Here we have considered the components to be along the x-axis and the y-axis. This representation is shown in the figure below.

If θ\theta be the angle made by the force vector, F\vec F to the x-axis, then following the figure from trigonometric properties we can see that the xx component of the vector is given as FcosθF\cos \theta , while the yy component is given as FsinθF\sin \theta .
Using these relations we are going to solve this question.
In the question, it is given that one of the components of the force if 10  N10\;N.
Hence we can say that any of the two rectangular components of force is 10  N10\;N.
Therefore let us consider the component along the x-axis to be 10  N10\;N.
Fcosθ=10\therefore F\cos \theta = 10
From the question, we know that the force vector makes an angle 60{60^\circ } with the above vector component. Hence the above equation can be written as,
Fcos60=10F\cos {60^\circ } = 10
Dividing both the sides with cos60\cos {60^\circ } we get,
F=10cos60F = \dfrac{{10}}{{\cos {{60}^\circ }}}
We know the value of cos60\cos {60^\circ } is 12\dfrac{1}{2}.
Substituting this in the above equation we get,
F=101/2F = \dfrac{{10}}{{1/2}}
Simplifying this equation further we get,
F=10×2F = 10 \times 2
F=20N\therefore F = 20N
Hence the magnitude of the given force vector is 20  N20\;N.

Therefore the correct answer is option (D) 20  N20\;N.

Note: Just like we can divide a vector into two rectangular components, we can also add two vectors with different directions into a resultant vector using the rectangle law of vector addition or subtraction. Triangle law is another method of vector addition.