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Question: If $Q_1(x) = x^2 + (k-29)x - k$ and $Q_2(x) = 2x^2 + (2k-43)x + k$ both are factors of cubic polynom...

If Q1(x)=x2+(k29)xkQ_1(x) = x^2 + (k-29)x - k and Q2(x)=2x2+(2k43)x+kQ_2(x) = 2x^2 + (2k-43)x + k both are factors of cubic polynomial, then largest value of kk is (where Q1(x)Q_1(x) and Q2(x)Q_2(x) are not perfect squares)

A

0

B

33

C

23

D

30

Answer

30

Explanation

Solution

For two quadratic polynomials to be factors of a cubic polynomial, they must share a common linear factor, which means they share a common root. By setting up equations Q1(α)=0Q_1(\alpha)=0 and Q2(α)=0Q_2(\alpha)=0 for a common root α\alpha, we solved for α\alpha in terms of kk, yielding α=k/5\alpha = -k/5. Substituting this back into Q1(α)=0Q_1(\alpha)=0 resulted in a quadratic equation in kk, 4k2+120k=0-4k^2 + 120k = 0, which gives k=0k=0 or k=30k=30. Finally, we verified that for both these values of kk, the discriminants of Q1(x)Q_1(x) and Q2(x)Q_2(x) are non-zero, satisfying the condition that they are not perfect squares. The largest of the valid kk values is 30.