Question

Two charges of magnitude each of 5 $\mu$C and 10 $\mu$C separated by distance of 1 m from each other, magnitude of force between the charges is 0.450 N

Answer 1

The given statement is true.

Answer 2

The force between two charges is calculated using Coulomb's Law: $F = k \frac{|q_1 q_2|}{r^2}$. Substituting the given values $q_1 = 5 \times 10^{-6} \, C$, $q_2 = 10 \times 10^{-6} \, C$, $r = 1 \, m$, and $k = 9 \times 10^9 \, N m^2 C^{-2}$, the calculated force is $F = (9 \times 10^9) \frac{(5 \times 10^{-6})(10 \times 10^{-6})}{(1)^2} = 450 \times 10^{-3} \, N = 0.450 \, N$. This matches the force stated in the question.