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Question: A person's eye is at a height of 1.5m. He stands in front of a 0.3m length plane mirror bottom of wh...

A person's eye is at a height of 1.5m. He stands in front of a 0.3m length plane mirror bottom of which is 0.8m above ground. Find the length of his image he will be able to see in this mirror.

A

0.3m

B

0.6m

C

0.8m

D

1.5m

Answer

0.6m

Explanation

Solution

The length of the image seen in a plane mirror is twice the vertical extent of the mirror visible to the observer's eyes. Given: Height of the person's eye from the ground, he=1.5h_e = 1.5 m Length of the plane mirror, Lm=0.3L_m = 0.3 m Height of the bottom of the mirror from the ground, hbm=0.8h_{bm} = 0.8 m

The height of the top of the mirror from the ground is htm=hbm+Lm=0.8+0.3=1.1h_{tm} = h_{bm} + L_m = 0.8 + 0.3 = 1.1 m.

Since the eye level (he=1.5h_e = 1.5 m) is above the top of the mirror (htm=1.1h_{tm} = 1.1 m), the observer can see the entire mirror. The vertical extent of the mirror visible to the observer is the full length of the mirror, which is Lm=0.3L_m = 0.3 m.

The length of the image seen in a plane mirror is twice the vertical extent of the mirror visible to the observer. Length of image seen = 2×(Visible mirror length)2 \times (\text{Visible mirror length}) Length of image seen = 2×0.32 \times 0.3 m = 0.60.6 m.

This length is independent of the observer's height, as long as their eyes are positioned to see the relevant parts of the mirror.