Question
Question: Given energy, E=g¹hmCn, where G= universal gravitational constant, h= Planck's constant, C= velocity...
Given energy, E=g¹hmCn, where G= universal gravitational constant, h= Planck's constant, C= velocity of light. Calculate the values of 1, m and n?

l = 1/8, m = 9/8, and n = -5/8
Solution
The energy E is given by the relation E=GlhmCn. To find the values of l, m, and n, we equate the dimensions on both sides of the equation.
The dimensions of the quantities are:
- Energy (E): [ML2T−2]
- Universal Gravitational Constant (G): [M−1L3T−2]
- Planck's constant (h): [ML2T−1]
- Velocity of light (C): [LT−1]
Substituting these dimensions into the given relation: [ML2T−2]=([M−1L3T−2])l([ML2T−1])m([LT−1])n [ML2T−2]=[M−l+mL3l+2m+nT−2l−m−n]
Equating the powers of M, L, and T on both sides: For M: 1=−l+m (1) For L: 2=3l+2m+n (2) For T: −2=−2l−m−n (3)
From (1), m=l+1. Substitute m into (3): −2=−2l−(l+1)−n −2=−3l−1−n n=3l−1 (4)
Substitute m and n into (2): 2=3l+2(l+1)+(3l−1) 2=3l+2l+2+3l−1 2=8l+1 1=8l⟹l=81
Now find m and n: m=l+1=81+1=89 n=3l−1=3(81)−1=83−1=−85
The values are l=81, m=89, and n=−85.