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Question: If Particle is slightly along x axis displaced and released. proved its motion is shm. Also find Tim...

If Particle is slightly along x axis displaced and released. proved its motion is shm. Also find Timeperiod.

Answer

T = 2π √(m a^3 / (4πε₀ Q q₀))

Explanation

Solution

  1. Calculate the net force on the particle at a small displacement xx from the origin along the x-axis due to the two fixed charges.

  2. Show that for small xx, the net force is a restoring force proportional to xx and opposite to the displacement, i.e., Fnet=KxF_{net} = -Kx. This proves that the motion is SHM. This occurs when the fixed charges and the particle charge have the same sign.

  3. Identify the force constant KK.

  4. Calculate the angular frequency ω=K/m\omega = \sqrt{K/m}.

  5. Calculate the time period T=2π/ωT = 2\pi/\omega.