Question
Question: quation of the straight line meeting the circle with centre at origin and radius equal to 5 in two p...
quation of the straight line meeting the circle with centre at origin and radius equal to 5 in two points at equal distances of 3 units from the point A(3, 4) is –
A
6x + 8y – 41 = 0
B
6x – 8y + 41 = 0
C
8x + 6y + 41 = 0
D
8x – 6y + 41 = 0
Answer
6x + 8y – 41 = 0
Explanation
Solution
Equation of given circle x2 + y2 = 25. Equation of circle with centre (3, 4) & radius 5 is
(x – 3)2 + (y – 4)2 = 25.
The required line is common chord of two circles i.e.
S1 – S2 = 0