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Question

Question: Two large sized charged plates have a charge density of + σ and -σ. The resultant force on the proto...

Two large sized charged plates have a charge density of + σ and -σ. The resultant force on the proton located midway between them will be:

A

σe/ϵ0\sigma e / \epsilon_0

B

σe/2ϵ0\sigma e / 2\epsilon_0

C

2σe/ϵ02\sigma e / \epsilon_0

D

zero

Answer

σe/ϵ0\sigma e / \epsilon_0

Explanation

Solution

Each plate produces an electric field of σ2ϵ0\frac{\sigma}{2\epsilon_0}. In the region between the plates, these fields add up to σϵ0\frac{\sigma}{\epsilon_0}. The proton experiences a force eσϵ0e\frac{\sigma}{\epsilon_0}.