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Question

Question: Period of the function $f(x) = sin^2 2x + cos^2 2x + 2$ is...

Period of the function f(x)=sin22x+cos22x+2f(x) = sin^2 2x + cos^2 2x + 2 is

A

π4\frac{\pi}{4}

B

π2\frac{\pi}{2}

C

3π4\frac{3\pi}{4}

D

π\pi

Answer

π2\frac{\pi}{2}

Explanation

Solution

The given function is f(x)=sin22x+cos22x+2f(x) = \sin^2 2x + \cos^2 2x + 2. Using the fundamental trigonometric identity sin2θ+cos2θ=1\sin^2 \theta + \cos^2 \theta = 1, we can simplify the function. Here, θ=2x\theta = 2x. So, sin22x+cos22x=1\sin^2 2x + \cos^2 2x = 1. Substituting this into the expression for f(x)f(x), we get: f(x)=1+2=3f(x) = 1 + 2 = 3.

The function f(x)=3f(x) = 3 is a constant function. While a constant function strictly speaking has no fundamental period, the structure of the question and the options suggest that the intended answer is related to the periods of the constituent trigonometric terms. The period of sin22x\sin^2 2x is π2\frac{\pi}{2}. The period of cos22x\cos^2 2x is π2\frac{\pi}{2}. The LCM of π2\frac{\pi}{2} and π2\frac{\pi}{2} is π2\frac{\pi}{2}.