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Question

Question: If D = $\begin{vmatrix} a^2+1 & ab & ac \\ ba & b^2+1 & bc \\ ca & cb & c^2+1 \end{vmatrix}$ then D ...

If D = a2+1abacbab2+1bccacbc2+1\begin{vmatrix} a^2+1 & ab & ac \\ ba & b^2+1 & bc \\ ca & cb & c^2+1 \end{vmatrix} then D =

A

1+a2+b2+c21+a^2+b^2+c^2

B

a2+b2+c2a^2+b^2+c^2

C

(a+b+c)2(a+b+c)^2

D

none

Answer

1+a2+b2+c21+a^2+b^2+c^2

Explanation

Solution

The determinant is evaluated by first transforming the matrix using row and column operations. Multiply rows by a,b,ca, b, c and divide by abcabc. Then take out a,b,ca, b, c from columns, which cancels abcabc. This results in a simpler matrix. Then apply R1R1+R2+R3R_1 \to R_1 + R_2 + R_3 and factor out the common term from R1R_1. Finally, perform column operations to create zeros, resulting in a triangular matrix whose determinant is easily calculated as the product of diagonal elements.