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Question

Question: If the sum of the roots of the equation $\lambda x^2 + 2x + 3\lambda = 0$ be equal to their product,...

If the sum of the roots of the equation λx2+2x+3λ=0\lambda x^2 + 2x + 3\lambda = 0 be equal to their product, then λ\lambda =

A

2/3

B

-2/3

C

3/2

D

-3/2

Answer

-2/3

Explanation

Solution

For a quadratic equation ax2+bx+c=0ax^2+bx+c=0, the sum of roots is b/a-b/a and the product of roots is c/ac/a. Given equation: λx2+2x+3λ=0\lambda x^2 + 2x + 3\lambda = 0. Here, a=λa = \lambda, b=2b = 2, c=3λc = 3\lambda. Sum of roots = 2/λ-2/\lambda. Product of roots = 3λ/λ3\lambda/\lambda. Given that sum of roots = product of roots: 2/λ=3λ/λ-2/\lambda = 3\lambda/\lambda. Assuming λ0\lambda \neq 0 (for it to be a quadratic equation), we can cancel λ\lambda from both sides: 2=3λ-2 = 3\lambda. Therefore, λ=2/3\lambda = -2/3.