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Question

Question: Integrate: $(7x^3 + 4x^2) dx$...

Integrate: (7x3+4x2)dx(7x^3 + 4x^2) dx

A

(7x4/4)+(4x2/4)+C(7x^4/4) + (4x^2/4) + C

B

(7x4/4)+(4x2/5)+C(7x^4/4) + (4x^2/5) + C

C

(7x4/4)+(4x3/3)+C(7x^4/4) + (4x^3/3) + C

D

7x4+(4x2/2)+C7x^4 + (4x^2/2) + C

Answer

(7x4/4)+(4x3/3)+C(7x^4/4) + (4x^3/3) + C

Explanation

Solution

To integrate (7x3+4x2)dx(7x^3 + 4x^2) dx, apply the linearity of integration and the power rule xndx=xn+1n+1+C\int x^n dx = \frac{x^{n+1}}{n+1} + C.

For the first term, 7x3dx=7x3+13+1=7x44\int 7x^3 dx = 7 \frac{x^{3+1}}{3+1} = \frac{7x^4}{4}.

For the second term, 4x2dx=4x2+12+1=4x33\int 4x^2 dx = 4 \frac{x^{2+1}}{2+1} = \frac{4x^3}{3}.

Combining these, the integral is 7x44+4x33+C\frac{7x^4}{4} + \frac{4x^3}{3} + C.