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Question: A long taut string is plucked at its centre. The pulse travelling on it can be described as $y(x, t)...

A long taut string is plucked at its centre. The pulse travelling on it can be described as y(x,t)=e(x+2t)2+e(x2t)2y(x, t) = e^{-(x + 2t)^2} + e^{-(x - 2t)^2}. Draw the shape of the string at time t = 0, a short time after t = 0 and a long time after t = 0.

Answer

At t=0t=0: A single, symmetric Gaussian hump centered at x=0x=0 with peak height 2. A short time after t=0t=0: The single hump starts to split into two overlapping humps, with a reduced peak at x=0x=0. A long time after t=0t=0: Two distinct, well-separated Gaussian humps, each with peak height approximately 1, located at x2tx \approx -2t and x2tx \approx 2t.

Explanation

Solution

The wave pulse is described by y(x,t)=e(x+2t)2+e(x2t)2y(x, t) = e^{-(x + 2t)^2} + e^{-(x - 2t)^2}. This function is a superposition of two Gaussian pulses: y1(x,t)=e(x+2t)2y_1(x, t) = e^{-(x + 2t)^2} and y2(x,t)=e(x2t)2y_2(x, t) = e^{-(x - 2t)^2}. The first pulse travels in the negative x-direction with speed v=2v=2, and the second pulse travels in the positive x-direction with speed v=2v=2.

At t=0t = 0, y(x,0)=ex2+ex2=2ex2y(x, 0) = e^{-x^2} + e^{-x^2} = 2e^{-x^2}. This is a single, symmetric Gaussian hump centered at x=0x=0 with a peak height of 2.

A short time after t=0t = 0 (e.g., t=Δt>0t = \Delta t > 0), y(x,Δt)=e(x+2Δt)2+e(x2Δt)2y(x, \Delta t) = e^{-(x + 2\Delta t)^2} + e^{-(x - 2\Delta t)^2}. The two pulses are close to each other and overlap significantly. The overall shape is still roughly a single hump, but the peak height at x=0x=0 is reduced, and the shape starts to flatten or develop a dip in the middle.

A long time after t=0t = 0 (e.g., t=T>0t = T > 0), y(x,T)=e(x+2T)2+e(x2T)2y(x, T) = e^{-(x + 2T)^2} + e^{-(x - 2T)^2}. The two pulses are well-separated and do not overlap. The string's shape consists of two distinct Gaussian humps, each with a peak height of approximately 1, located around x=2Tx = -2T and x=2Tx = 2T.