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Question: Two plates are 20 cm apart and the potential difference between them is 10 V. The electric field bet...

Two plates are 20 cm apart and the potential difference between them is 10 V. The electric field between the plates is

A

50 Vm−1^{-1}

B

500 Vm−1^{-1}

C

0.5 Vm−1^{-1}

D

20 Vm−1^{-1}

Answer

50 Vm−1^{-1}

Explanation

Solution

The electric field (E) between two parallel plates is related to the potential difference (V) across them and the distance (d) between them by the formula:

E=VdE = \frac{V}{d}

Given:

Potential difference, V = 10 V Distance between plates, d = 20 cm

First, convert the distance from centimeters to meters:

d=20 cm=20×10−2 m=0.2 md = 20 \text{ cm} = 20 \times 10^{-2} \text{ m} = 0.2 \text{ m}

Now, substitute the values into the formula:

E=10 V0.2 m=50 Vm−1E = \frac{10 \text{ V}}{0.2 \text{ m}} = 50 \text{ Vm}^{-1}