Question

The P-V diagram of a diatomic ideal gas system going under cyclic process as shown in figure. The work done during an adiabatic process $CD$ is (use $\gamma = 1.4$)

Answer 1

500

Answer 2

The work done during an adiabatic process is given by $W = \frac{P_1 V_1 - P_2 V_2}{\gamma - 1}$. For process CD, $P_D = 200 \, N/m^2$, $V_D = 3 \, m^3$, $P_C = 100 \, N/m^2$, $V_C = 4 \, m^3$, and $\gamma = 1.4$. $W_{CD} = \frac{(200)(3) - (100)(4)}{1.4 - 1} = \frac{600 - 400}{0.4} = \frac{200}{0.4} = 500 \, J$.