Solveeit Logo
Login

Question

Mathematics Question on Intersecting Lines and Non-intersecting Lines

Q is a point on the line BD dividing the segment internally. AB, PQ and CD are drawn perpendicular to BD. If AB = a, PQ = b and CD = c, then

A

1a+1b=1c\frac{1}{a} + \frac{1}{b} = \frac{1}{c}

B

1a+1c=1b\frac{1}{a} + \frac{1}{c} = \frac{1}{b}

C

1a−1b=1c\frac{1}{a} - \frac{1}{b} = \frac{1}{c}

D

1b+1c=1a\frac{1}{b} + \frac{1}{c} = \frac{1}{a}

Answer

1a+1c=1b\frac{1}{a} + \frac{1}{c} = \frac{1}{b}

Explanation

Solution

The correct option is (B): 1a+1c=1b\frac{1}{a} + \frac{1}{c} = \frac{1}{b}