Question

Q Dalton Determined the composition of water as H→12.5%, O→87.5% By may f losidered the Chemical formula of water as HO At. Mauss of O хуген →100 gm

Answer 1

The atomic mass of Hydrogen would be $\frac{100}{7}$ gm (or approximately 14.29 gm).

Answer 2

Explanation of the Solution:

1. Determine the mass ratio of Hydrogen to Oxygen: Given the composition of water by mass: Hydrogen (H) = 12.5%, Oxygen (O) = 87.5%. The mass ratio of H : O is 12.5 : 87.5. To simplify this ratio, divide both sides by 12.5: $\frac{12.5}{12.5} : \frac{87.5}{12.5}$ $1 : 7$ So, the mass ratio of H to O in water, according to Dalton's determination, is 1:7.

2. Relate mass ratio to atomic mass ratio using Dalton's assumed formula: Dalton considered the chemical formula of water as HO. This means one atom of Hydrogen combines with one atom of Oxygen to form one molecule of water. Therefore, the ratio of their atomic masses ($AM_H : AM_O$) must be equal to their mass ratio in the compound. $AM_H : AM_O = 1 : 7$ This can be written as: $\frac{AM_H}{AM_O} = \frac{1}{7}$

3. Calculate the atomic mass of Hydrogen: Given that the atomic mass of Oxygen ($AM_O$) is 100 gm (relative units). Substitute this value into the equation from step 2: $\frac{AM_H}{100} = \frac{1}{7}$ $AM_H = \frac{100}{7}$

Therefore, based on Dalton's data and assumptions, the atomic mass of Hydrogen would be 100/7.