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Question: A battery of emf V and internal resistance r is connected to N identical bulbs, all in parallel. Res...

A battery of emf V and internal resistance r is connected to N identical bulbs, all in parallel. Resistance of each bulb is R. It is observed that maximum cumulative power is dissipated in the bulbs if N = 10. Can we say that r=R10r=\frac{R}{10}

Answer

Yes, r=R10r = \frac{R}{10}.

Explanation

Solution

  1. Effective Resistance:
    For N bulbs in parallel, the effective resistance is

    Rparallel=RNR_{\text{parallel}}=\frac{R}{N}
  2. Maximum Power Transfer:
    According to the maximum power transfer theorem, maximum power is delivered to the load when the load resistance equals the battery's internal resistance.

    RN=r\frac{R}{N}=r
  3. Given Condition:
    It is observed that maximum power is dissipated when N=10N=10. Substituting, we get

    R10=rr=R10\frac{R}{10}=r \quad \Rightarrow \quad r=\frac{R}{10}