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Question: Let $$f(x) = \begin{cases} \cot^{-1}x, |x| \ge 1 \\ \frac{1}{2}|x| + \frac{\pi}{4} - \frac{1}{2}, |x...

Let f(x)={cot1x,x112x+π412,x<1f(x) = \begin{cases} \cot^{-1}x, |x| \ge 1 \\ \frac{1}{2}|x| + \frac{\pi}{4} - \frac{1}{2}, |x| < 1 \end{cases} then number of values of x, (xRx \in R) which do not belong to the domain of f(x)f'(x) is

Answer

3

Explanation

Solution

The function f(x)f(x) is analyzed for differentiability at points where its definition changes (x=1,x=1x=-1, x=1) and where the absolute value function changes its behavior (x=0x=0).

  • At x=1x=-1, the function is discontinuous, hence not differentiable.
  • At x=0x=0, the left and right derivatives of the piecewise linear part are different (12-\frac{1}{2} and 12\frac{1}{2}), hence not differentiable.
  • At x=1x=1, the function is continuous, but the left and right derivatives are different (12\frac{1}{2} and 12-\frac{1}{2}), hence not differentiable. Thus, f(x)f'(x) is undefined at x=1,0,1x=-1, 0, 1.