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Question: Q. 11 Calculate the wavelength of the radiation that would cause photo dissociation of chlorine mole...

Q. 11 Calculate the wavelength of the radiation that would cause photo dissociation of chlorine molecule if the extClextCl ext{Cl}- ext{Cl} bond energy is 241extKJ/extmol241 ext{KJ} / ext{mol}.

A

594nm594\, nm

B

640nm640\, nm

C

700nm700\, nm

D

494nm494\, nm

Answer

494nm494\, nm

Explanation

Solution

Energy required for 1Cl21\, Cl_2 molecule =242×103NA= \frac{242\times10^{3}}{N_{A}} Joules. This energy is contained in photon of wavelength ?λ??\lambda?. hcλ=E6.626×1034×3×108λ=242×1036.022×1023\frac{hc}{\lambda} = E \Rightarrow \frac{6.626\times 10^{-34}\times 3\times 10^{8}}{\lambda} = \frac{242\times 10^{3}}{6.022\times 10^{23}} λ=4947?494nm\lambda = 4947\,? \approx 494\, nm