Question
Question: p<sub>1</sub>, p<sub>2</sub> are lengths of perpendicular from foci on tangent to ellipse and p<sub>...
p1, p2 are lengths of perpendicular from foci on tangent to ellipse and p3, p4 are perpendiculars from extremities of major axis and p from centre of ellipse on same tangent, then p3p4−p2p1p2−p2 equals
A
e
B
e
C
e2
D
None of these
Answer
e2
Explanation
Solution
Let tangent is y = mx + c
\ p = m2+1c, p1 = 1+m2c+aem,
p2 = 1+m2∣c–aem∣, p3 = 1+m2∣am+c∣,
p4 = 1+m2∣c–am∣
Now put values in p3p4−p2p1p2−p2