Question

Prussian blue is formed when.

• A. Ferrous sulphate reacts with $FeCl_{3}$
• B. Ferric sulphate reacts with $K_{4}\left\lbrack Fe(CN)_{6} \right\rbrack$
• C. Ferrous ammonium sulphate reacts with $FeCl_{3}$
• D. Ammonium sulphate reacts with $FeCl_{3}$

Answer 1

Answer: (B)

Ferric sulphate reacts with $K_{4}\left\lbrack Fe(CN)_{6} \right\rbrack$

Answer 2

$Fe_{2}(SO_{4})_{3} \rightarrow 2Fe^{3 +} + 3SO_{4}^{2 -}$

$K_{4}\lbrack Fe(CN)_{6}\rbrack + 2Fe^{3 +} \rightarrow \underset{\text{Prussionblue}}{Fe_{4}\lbrack Fe(CN)_{6}\rbrack_{3}}$.