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Question

Mathematics Question on Integrals of Some Particular Functions

Prove that the value of the integral, 02a[f(x)/f(x)+f(2ax)]dx\int\limits_0^{2a} [f(x)/ f(x) + f(2a-x)] dx is equal to a

A

162

B

132

C

21 32

D

2123

Answer

162

Explanation

Solution

Let I=02af(x)f(x)+f(2ax)dxI=\int \limits_0^{2a} \frac{f(x)}{ f(x )+f(2a -x )} dx .......(i)
I=02af(2ax)f(x)+f(2ax)dxI=\int \limits_0^{2a} \frac{f( 2a-x)}{ f(x )+f(2a -x )} dx ........(ii)
On adding Eqs. (i) and (ii), we get
2I=02a1dx=2aI=a2I= \int \limits_0^{2a} 1 dx = 2a \Rightarrow I=a