Question
Question: Prove that \({2.7^n} + {3.5^n} - 5\) is divisible by 24 for all \(n \in N\)....
Prove that 2.7n+3.5n−5 is divisible by 24 for all n∈N.
Solution
Hint:Use the concept of mathematical induction by substituting the values of n as 1, k and k+1. Check whether P(1) holds true or not, if yes then assume then P(k) also holds true, if with this assumption P(k+1) holds true then its proved that 2.7n+3.5n−5 is divisible by 24, under given conditions.
Complete step-by-step answer:
Given expression
2.7n+3.5n−5
Proof –
Let,
P(n)=2.7n+3.5n−5 Is divisible by 24.
We note that P (n) is true when n = 1,
Since P (1) = 14 + 15 – 5 = 24 which is divisible by 24.
Assume that it is true for P (k).
I.e. P(k)=2.7k+3.5k−5=24q.................... (1), when q∈N
Now according to the mathematical induction principle we have to prove it is also true for P (k + 1) whenever p (k) is true.
Now substitute in place of k, (k + 1) we have,
⇒P(k+1)=2.7k+1+3.5k+1−5
⇒2.7.7k+3.5.5k−5
Now add and subtract by 3.7.5k−7.5 we have,
⇒2.7.7k+3.5.5k−5+3.7.5k−7.5−(3.7.5k−7.5)
⇒7(2.7k+3.5k−5)+3.5.5k−5−(3.7.5k−7.5)
Now from equation (1) we have,
⇒7(24q)+3.5.5k−5−3.7.5k+7.5
⇒7(24q)−2.3.5k−5+35
⇒7(24q)−2.3.5k+30
⇒7(24q)−6(5k−5)
Now as we know that (5k−5) is a multiple of 4 so in place of that we can write (4p) where (p) belongs to the natural number.
⇒7(24q)−6(4p)
⇒24(7q−p)
So as we see this is a multiple of 24.
Thus P (k + 1) is true whenever P (k) is true.
So according to the principle of mathematical induction 2.7n+3.5n−5 is divisible by 24.
Hence proved.
Note – Mathematical induction is a mathematical technique which is used to prove a statement, a formula or a theorem is true for every natural number. The key point is the condition of natural numbers, so if a proof is to be done and the condition given holds true for natural number only than always think of the mathematical induction