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Question: Propene,\(\mathrm { CH } _ { 3 } - \mathrm { CH } = \mathrm { CH } _ { 2 }\) can be converted to 1-p...

Propene,CH3−CH=CH2\mathrm { CH } _ { 3 } - \mathrm { CH } = \mathrm { CH } _ { 2 } can be converted to 1-propanol by oxidation. Which set of reagents among the following is ideal to effect the conversion

A

Alkaline KMnO4\mathrm { KMnO } _ { 4 }

B

B2H6B _ { 2 } H _ { 6 } and alkaline H2O2\mathrm { H } _ { 2 } \mathrm { O } _ { 2 }

C

dust

D

OsO4/CH4,Cl2\mathrm { OsO } _ { 4 } / \mathrm { CH } _ { 4 } , \mathrm { Cl } _ { 2 }

Answer

B2H6B _ { 2 } H _ { 6 } and alkaline H2O2\mathrm { H } _ { 2 } \mathrm { O } _ { 2 }

Explanation

Solution

Hydroboration oxidation (Industrial preparation of alcohol)

3CH3CH=CH2+12 B2H6→ ether Dry(CH3CH2CH3)3 B3 \mathrm { CH } _ { 3 } \mathrm { CH } = \mathrm { CH } _ { 2 } + \frac { 1 } { 2 } \mathrm {~B} _ { 2 } \mathrm { H } _ { 6 } \xrightarrow [ \text { ether } ] { \mathrm { Dry } } \left( \mathrm { CH } _ { 3 } \mathrm { CH } _ { 2 } \mathrm { CH } _ { 3 } \right) _ { 3 } \mathrm {~B}

(CH3CH2CH3)3 B→H2O23CH3CH2CH2−OH\left( \mathrm { CH } _ { 3 } \mathrm { CH } _ { 2 } \mathrm { CH } _ { 3 } \right) _ { 3 } \mathrm {~B} \xrightarrow { \mathrm { H } _ { 2 } \mathrm { O } _ { 2 } } 3 \mathrm { CH } _ { 3 } \mathrm { CH } _ { 2 } \mathrm { CH } _ { 2 } - \mathrm { OH }