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Question

Question: Propene on treatment with HBr gives....

Propene on treatment with HBr gives.

A

Isopropyl bromide

B

Propyl bromide

C

1, 2-dibromoethane

D

None of the above

Answer

Isopropyl bromide

Explanation

Solution

CH3CH=CH2+HBrMarko wnikoff’s ruleCH3CHBrCH3CH_{3} - CH = CH_{2} + HBr\overset{\rightarrow}{\quad\begin{array}{r} \text{Marko wnikoff's} \\ \text{ rule} \end{array}\quad}CH_{3} - \underset{Br}{\underset{|}{CH}} - CH_{3}