Question

Propene, $CH_3 - CH = CH_2$ can be converted into 1-propanol by oxidation. Indicate which set of reagents amongst the following is ideal to affect the above conversion?

• A. $KMnO_4$ (alkaline)
• B. Osmium tetroxide $(Os O_4 /CH_2 Cl_2)$
• C. $B_2 H_6$ and $H_2 O_2$
• D. $O_3/Zn$

Answer 1

Answer: (C)

$B_2 H_6$ and $H_2 O_2$

Answer 2

$3CH_3\, CH= CH_2 \xrightarrow{B_2H_6}$
\hspace40mm(CH_3- CH_2- CH_2)_3 B
\hspace10mm \xrightarrow{H_2 O_2/OH^-} CH_3- CH_2- CH_2- OH
\hspace50mm _{}^{Propan.1.o1}
Here, Half mol of $(B_2 H_6)$ diborane react with
propane by Markownikoffs addition it gives
tripropyl borane called hydroboration. In presence of
$H_2 O_2$ in basic medium tripropyl borane gives
alcohol. Remember that product is
Anti-Markownikoffs rule that is 1-propanol.
Reaction is called hydroboration oxidation.