Question

Propane+Br2/hv

Answer 1

The reaction produces a mixture of brominated propanes. Major Product: 2-bromopropane ($CH_3CHBrCH_3$). Minor Product: 1-bromopropane ($CH_3CH_2CH_2Br$).

Answer 2

Free radical bromination of propane ($CH_3CH_2CH_3$) with $Br_2/hv$ yields 2-bromopropane ($CH_3CHBrCH_3$) as the major product and 1-bromopropane ($CH_3CH_2CH_2Br$) as the minor product. This selectivity arises from the greater stability of the secondary radical ($CH_3\dot{C}HCH_3$) intermediate formed by abstracting a secondary hydrogen, compared to the primary radical ($\dot{C}H_2CH_2CH_3$) formed by abstracting a primary hydrogen.