Question

Products (X and Y) of the following reactions (I and II) are : I. $\underset{\text{(Cold and dil.)}}{{2NaOH}}+ Cl_{2} \to Nacl+X+H_{2}O$ II. $\underset{\text{(Hot and cone.)}}{{6NaOH}}+ 3Cl_{2} \to Nacl+Y+3H_{2}O$

• A. $X = NaCIO_{3}$ and $Y =NaOCI$
• B. $X =NaCIO$ and $V =NaOCI_{3}$
• C. $X =NaHCIO_{3}$ and $Y =NaOCI$
• D. $X = NaCIO_{3}$ and $Y = NaHCIO_{3}$

Answer 1

Answer: (B)

$X =NaCIO$ and $V =NaOCI_{3}$

Answer 2

Chlorine with cold and dilute alkali, $NaOH$ forms a mixture of chloride and hypochlorite as
$Cl_{2}+2NaOH(dil) { ->[Cold] } NaCl+\underset{\text{Sodium hypochlorite ( X)}}{{NaOCl+H_{2}O}}$
Chlorine with hot and concentrated alkali, $NaOH$ forms a mixture of chloride and chlorate as
$3Cl_{2}+3NaOH(conc.) { ->[Hot] } 5NaCl+\underset{\text{Sodium chlorate ( Y)}}{{NaClO_{3}+3H_{2}O}}$