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Question

Question: $\prod_{n=1}^{k}(1+x^n)^n$...

n=1k(1+xn)n\prod_{n=1}^{k}(1+x^n)^n

Answer

n=1k(1+xn)n\prod_{n=1}^{k}(1+x^n)^n

Explanation

Solution

The given expression is a product:

n=1k(1+xn)n\prod_{n=1}^{k}(1+x^n)^n

This notation means we multiply terms of the form (1+xn)n(1+x^n)^n for each integer value of nn from 11 to kk.

Let's write out the terms of the product:

For n=1n=1, the term is (1+x1)1=(1+x)(1+x^1)^1 = (1+x).

For n=2n=2, the term is (1+x2)2(1+x^2)^2.

For n=3n=3, the term is (1+x3)3(1+x^3)^3.

...

For n=kn=k, the term is (1+xk)k(1+x^k)^k.

So, the product can be written as:

(1+x)1(1+x2)2(1+x3)3(1+xk)k(1+x)^1 \cdot (1+x^2)^2 \cdot (1+x^3)^3 \cdot \ldots \cdot (1+x^k)^k

This expression represents a polynomial in xx if kk is a positive integer. For example:

  • If k=1k=1, the product is (1+x)(1+x).
  • If k=2k=2, the product is (1+x)(1+x2)2=(1+x)(1+2x2+x4)=1+x+2x2+2x3+x4+x5(1+x)(1+x^2)^2 = (1+x)(1+2x^2+x^4) = 1+x+2x^2+2x^3+x^4+x^5.

This type of product does not simplify into a common closed-form expression using standard mathematical identities or formulas. The terms in the product, (1+xn)n(1+x^n)^n, are distinct for different values of nn and do not exhibit a pattern that allows for cancellation (like in telescoping products) or combination into a simpler form (like in geometric series products).

Therefore, the given expression is already in its most compact and general form. There is no simpler algebraic closed-form solution for this product for arbitrary kk and xx.

The expression itself is the 'solution' in the sense that it's the most simplified and general representation of the product.