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Chemistry Question on Enthalpy change

Problem FigAn ideal gas undergoes a cyclic transformation starting from the point AA and coming back to the same point by tracing the path ABCAA \to B \to C \to A as shown in the diagram. The total work done in the process is \\_\\_\\_\\_ J.

Answer

The work done by an ideal gas in a cyclic process can be calculated by finding the area enclosed in the P-V diagram.

For the given P-V diagram:

W=12×(3010)×(3010)=200kPadm3W = \frac{1}{2} \times (30 - 10) \times (30 - 10) = 200 \, \text{kPa} \cdot \text{dm}^3

Converting units:

W=200×1000PaL-bar=200JW = 200 \times 1000 \, \text{Pa} \cdot \text{L-bar} = 200 \, \text{J}