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Question

Question: Prime numbers between \[1\] to \[20\] .What is the probability of getting an odd number?...

Prime numbers between 11 to 2020 .What is the probability of getting an odd number?

Explanation

Solution

Hint : In order to solve this question, first of all we list down all the prime numbers from 11 to 2020 . After that we will find out what are the favourable outcomes and total outcomes for the event of getting an odd number and then finally use the formula of finding a probability of event i.e., P(E)=Number of favourable outcomesNumber of total outcomesP\left( E \right) = \dfrac{{Number{\text{ }}of{\text{ }}favourable{\text{ }}outcomes}}{{Number{\text{ }}of{\text{ }}total{\text{ }}outcomes}} and hence we get the required result.

Complete step-by-step answer :
First of all, let’s recall the definition of prime numbers.
A number whose factors are 11 and itself only is known as a prime number.
So, now lists down all the prime numbers from 11 to 2020 .
Therefore, we get 2, 3, 5, 7, 9, 11, 13, 17, 192,{\text{ }}3,{\text{ }}5,{\text{ }}7,{\text{ }}9,{\text{ }}11,{\text{ }}13,{\text{ }}17,{\text{ }}19
Now, we have to find out the probability of getting an odd number.
We know that odd numbers are those which cannot be divided by 22
So, now lists down all the odd numbers from the set of prime numbers between 11 to 2020
Therefore, we get
3, 5, 7, 9, 11, 13, 17, 193,{\text{ }}5,{\text{ }}7,{\text{ }}9,{\text{ }}11,{\text{ }}13,{\text{ }}17,{\text{ }}19
Thus, favourable outcomes of getting an odd number equals to 3, 5, 7, 9, 11, 13, 17, 193,{\text{ }}5,{\text{ }}7,{\text{ }}9,{\text{ }}11,{\text{ }}13,{\text{ }}17,{\text{ }}19
Therefore, number of favourable outcomes of getting an odd number =8 = 8
And according to the question, number of total outcomes =9 = 9
Now by using the formula of finding a probability of event i.e., P(E)=Number of favourable outcomesNumber of total outcomesP\left( E \right) = \dfrac{{Number{\text{ }}of{\text{ }}favourable{\text{ }}outcomes}}{{Number{\text{ }}of{\text{ }}total{\text{ }}outcomes}}
we calculate the probability of getting an odd number
Therefore, we get
P(E)=Number of favourable outcomesNumber of total outcomes =89P\left( E \right) = \dfrac{{Number{\text{ }}of{\text{ }}favourable{\text{ }}outcomes}}{{Number{\text{ }}of{\text{ }}total{\text{ }}outcomes}}{\text{ }} = \dfrac{8}{{9}}
On simplifying, we get
P(E)=89P\left( E \right) = \dfrac{8}{{9}}
So, the correct answer is P(E)=89P\left( E \right) = \dfrac{8}{{9}}”.

Note : The common mistake students make while solving this question is one might confuse the definition of prime numbers with the definition of odd numbers. Also, some students make the mistake of considering all the odd numbers as prime numbers, but this is wrong. For example, numbers like 9, 159,{\text{ }}15 are odd but not prime. So, this mistake must be avoided. And also remember that 11 is not considered as a prime number. Except 2 all prime numbers are odd.