Question

Primary alkyl halide $C_{4}H_{9}Br(X)$ reacts with alc. KOH to give compound (Y). (Y) reacts with HBr to give compound (Z) which is an isomer of (X). when (X) reacts with Na metal it gives compounds (P). (X), (Y), (Z) and (P) are.

• A. (A) X: C4H9Br, Y: CH3-CH=CH2, Z: CH3-CHBr-CH3, P: C8H18
• A. (B) X: CH3-CH2-CH2-CH2Br, Y: CH3-CH=CH-CH3, Z: CH3-CH2-CH2-CH2Br, P: C5H10
• A. (C) X: CH3-CH2-CHBr-CH3, Y: CH3-CH=CH-CH3, Z: CH3-CH2-CH2-CH2Br, P: C7H14
• A. (D) X: CH3-CH(CH3)CH2Br, Y: CH3-CH=CH-CH3, Z: CH3-CHBr-CH2-CH3, P: C6H12

Answer 1