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Question: Pressure is determined as force per unit area of the surface. The SI units of pressure, pascal is as...

Pressure is determined as force per unit area of the surface. The SI units of pressure, pascal is as shown below:
1Pa=1Nm21Pa=1N{{m}^{-2}}
If the mass of air at sea level is 1034 g, calculate the pressure in pascal.

Explanation

Solution

Hint: We know that Pascal is the SI unit of pressure, which is N/m2N/{{m}^{2}}. And pressure is the force applied per unit area or the weight per unit area.

Complete step-by-step answer:
It is given that pressure is force per unit area by any liquid, gas or solid i.e. FA\dfrac{F}{A}. And the SI unit of pressure is pascal (N/m2N/{{m}^{2}}=kgm/sec2kgm/{{\sec }^{2}}).
Let’s assume there is one surface at sea level of the unit area (1m21{{m}^{2}}). So, the force exerted on this surface is pressure. Because,
P(pressure)=FAP(pressure)=\dfrac{F}{A} , if we put value ofA=1m2A=1{{m}^{2}},
Then, P=FP=F.
And it is given that at sea level pressure is due to air. Force at the surface of sea level F=mgF=mg and P=FP=F. And given that mass of 1cm21034g,1c{{m}^{2}}\to 1034g,
104m21034g{{10}^{-4}}{{m}^{2}}\to 1034g
Then for, 1m210340kg1{{m}^{2}}\to 10340kg
So, the force F=(10340kg)×(9.8msec2)F=(10340kg)\times (9.8m{{\sec }^{-2}})
=101,332 N
PP = 101,332 Nm2N{{m}^{-2}}
= 101,332 PaPa
PP=1.01332×105Pa1.01332\times {{10}^{5}}Pa, this is the standard atmospheric pressure at sea level.
1atm = 1.01332×105Pa1.01332\times {{10}^{5}}Pa

Note: Here, we will take the standard value of gravity (g) = 9.8msec29.8m{{\sec }^{-2}} not 10msec210m{{\sec }^{-2}}. Pressure decreases as the altitude or height from the sea level increases from the sea level.