Pressure inside a soap bubble is greater than the pressure o... | Physics | SolveeIt | Solveeit

Today, August 18

Question

Pressure inside a soap bubble is greater than the pressure outside by an amount;(given : R = Radius of bubble, S = Surface tension of bubble)

A

$\frac{4S}{R}$

B

$\frac{4R}{S}$

C

$\frac{S}{R}$

D

$\frac{2S}{R}$

Answer

$\frac{4S}{R}$

Explanation

Solution

For a soap bubble, there are two liquid-air surfaces, so the excess pressure $\Delta P$ inside the bubble is given by:
$\Delta P = 2 \left( \frac{2S}{R} \right) = \frac{4S}{R}$