Pressure head in Bernoulli's equation is | Physics | SolveeIt

Question

Pressure head in Bernoulli's equation is

$\frac{P_{\rho}}{g}$

$\frac{P}{\rho g}$

$\rho g$

$P\rho g$

Answer

$\frac{P}{\rho g}$

Explanation

Solution

Bernoulli's equation is $P+\rho gh+\frac{1}{2}\rho v^{2}$ = a constant, or $\frac{P}{\rho g}+h+\frac{1}{2} \frac{v^{2}}{g}$ = constant, Here, $\frac{P}{\rho g}$ is called pressure head.

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Solution