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Question

Chemistry Question on Ideal gas equation

Pressure exerted by a perfect gas is equal to

A

mean kinetic energy per unit volume

B

half of mean kinetic energy per unti volume

C

two third of mean kinetic energy per unit volume

D

one third of mean kinetic energy per unit volume

Answer

two third of mean kinetic energy per unit volume

Explanation

Solution

P=2/3(1/2mNvrms2)VP = \frac{2/3 (1/2 mN \, v^2_{rms})}{V} where m is mass of molecule of gas, N is number of molecules in gas &vrmsv_{rms} is root mean square velocity of the molecule.