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Question

Question: owing in three infinitely long wires along positive x, y and z directions. The magnetic field would ...

owing in three infinitely long wires along positive x, y and z directions. The magnetic field would be

Answer

The question is incomplete as it does not specify the point where the magnetic field is to be calculated or the magnitude of the current. Assuming the current in each wire is I along the positive x, y, and z directions respectively, the magnetic field B at a general point (x, y, z) is:

B=μ0I2π[zj^+yk^y2+z2+zi^xk^x2+z2+yi^+xj^x2+y2]\vec{B} = \frac{\mu_0 I}{2 \pi} \left[ \frac{-z\hat{j} + y\hat{k}}{\sqrt{y^2 + z^2}} + \frac{z\hat{i} - x\hat{k}}{\sqrt{x^2 + z^2}} + \frac{-y\hat{i} + x\hat{j}}{\sqrt{x^2 + y^2}} \right]

If the question implicitly refers to the magnetic field at a point symmetric with respect to the axes, such as (a, a, a) where a ≠ 0, the total magnetic field is 0.

Explanation

Solution

The magnetic field due to each infinitely long straight wire is calculated using the formula B=μ0I2πrB = \frac{\mu_0 I}{2 \pi r} and the right-hand rule for direction. The perpendicular distance rr from each wire to the point (x,y,z)(x, y, z) is determined. The vector components of the magnetic field from each wire (Bx\vec{B_x}, By\vec{B_y}, Bz\vec{B_z}) are found. The total magnetic field is the vector sum of these individual fields. For a point (a,a,a)(a, a, a) (where a0a \neq 0), the fields from each wire cancel out vectorially, resulting in a net magnetic field of zero.