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Question

Mathematics Question on Area Of A Parallelogram

PQRS is a parallelogram (see the given figure). QM is the height from Q to SR and QN is the height from Q to PS. If SR = 1212 cm and QM = 7.67.6 cm. Find:

  1. the area of the parallelogram PQRS
  2. QN, if PS = 8 cm

PQRS parallelogram

Answer

(a) Area of parallelogram=Base ×Height \text{Area of parallelogram} = \text{Base }× \text{Height }
= SR×QMSR × QM
= 7.6×12=91.2  cm27.6 × 12 = 91.2 \;cm^2


(b) Area of parallelogram=Base ×Height \text{Area of parallelogram} = \text{Base }× \text{Height }
= PS×QNPS × QN
= 91.2  cm291.2 \;cm^2
QN×8=91.2\Rightarrow QN × 8 = 91.2
QN=91.28=11.4  cm\Rightarrow QN = \frac{91.2}{8}=11.4\;cm