Mathematics Question on Right-Angled Triangles And Pythagoras Property

Question

PQR is a triangle right angled at P. If PQ = 10 cm and PR = 24 cm, find QR.

Accepted Answer

triangle PQR
By applying Pythagoras theorem in $Δ\;PQR$ ,

$\Rightarrow$ $(PQ)^2+ (PR)^2= (RQ)^2$

$\Rightarrow$ $(10)^2+ (24)^2= RQ^2$

$\Rightarrow$ $100 + 576 = (QR)^2$

$\Rightarrow$ $676 = (QR)^2$

$\Rightarrow$$QR= 26$ $cm$