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Physics Question on Power

Power transmitted by a V-belt drive is determined by the effective pull and the belt speed, as given by the following equation

A

p=(T2−T1)v1000p=\frac{(T_2-T_1)v}{1000}

B

p=(T1−T2)v1000p=\frac{(T_1-T_2)v}{1000}

C

p=(T1−T22)v1000p=\frac{(T_1-T_2^2)v}{1000}

D

p=(T12−T2)v1000p=\frac{(T_1^2-T_2)v}{1000}

Answer

p=(T1−T2)v1000p=\frac{(T_1-T_2)v}{1000}

Explanation

Solution

The correct option is(B): p=(T1−T2)v1000p=\frac{(T_1-T_2)v}{1000}