Question
Question: Power emitted by a black body at temperature \(50\;^\circ {\rm{C}}\) is P. Now, temperature is doubl...
Power emitted by a black body at temperature 50∘C is P. Now, temperature is doubled i.e. the temperature of the blackbody becomes 100∘C. Now power emitted is:
(a). greater than P but less than 16P
(b). greater than 16P
(c). P
(d). 16P
Solution
Here we are using Stefan’s Boltzmann law. The power emitted depends on the temperature at which the body is. In this law temperature is expressed in Kelvins.
Complete step by step answer:
Given the temperature of black body in the first considered case is 50∘C. Let P be the power emitted by the body at this temperature. The second case is when the temperature was doubled. That is when the temperature is 100∘C. Let P2 be the power emitted by the body at this temperature.
As we know, according to Stefan’s Boltzmann law, the power emitted by a black body is directly proportional to the fourth power of temperature. The law can further be expressed as,
P∝T4
So in this case, the above expression can take the form as,
PP2=T14T24
Here the temperatures are expressed in Celsius.
But in Stefan’ expression the temperatures are to be expressed in Kelvin. So the given temperatures are to be converted to Kelvins by adding 273. Thus we have,
T2=100∘C ⇒T2=273+100 ⇒T2=373K
⇒T1=50∘C ⇒T1=273+50 ⇒T1=323K
Thus the above expressed relation PP2=T14T24 now becomes,
PP2=(323373)4 ⇒PP2=24 ∴P2=24P
Therefore value of power emitted in case two is greater than P but less than 16. So the correct option is: (a) greater than P but less than 16P.
Note: The temperatures are to be converted into Kelvins and the unit of power is calculated in Watts. Stefan's Boltzmann law, also called Stefan’s law is only applicable to black bodies. When the Stefan’ law is related to power emitted the Wien’s displacement law deals with the thermal energy of a body.