Question
Physics Question on Electric Power
Power dissipated in an LCR series circuit connected to an a.c. source of emf ε is :
A
ε2R/R2+(Lω−Cω1)2
B
ε2R/[R2+(Lω−Cω1)2]
C
ε2[R2+(Lω−Cω1)2]/R
D
Rε2[R2+(Lω−Cω1)2]
Answer
ε2R/[R2+(Lω−Cω1)2]
Explanation
Solution
Pav=Erms⋅Irmscosϕ
=ε⋅zε⋅zR=z2ε2R
=R2+(ωL−ωC1)2ε2R