Solveeit Logo

Question

Physics Question on Electric Power

Power dissipated across the 8Ω8 \,\Omega resistor in the circuit shown here is 2 watt. The power dissipated in watt units across the 3Ω3 \,\Omega resistor is :-

A

3

B

2

C

1

D

0.5

Answer

3

Explanation

Solution

As voltage drop across
8Ω=2×8=4V(P=V2R)8 \Omega=\sqrt{2 \times 8}=4 V \left(\because P =\frac{ V ^{2}}{ R }\right)
Therefore voltage drop across 3Ω=3V3 \Omega=3 V
[4V[\because 4 V is divided in ratio of resistances between 1Ω1 \Omega and 3Ω]3 \Omega]
Hence power dissipated in 3Ω=(3)23=33 \Omega=\frac{(3)^{2}}{3}=3 watt